
Graphing Tangent, Cotangent, Secant, and Cosecant - Socratic
Questions and Videos on Graphing Tangent, Cotangent, Secant, and Cosecant, within Trigonometry
How do you determine if rolles theorem can be applied to #f
How do you determine if rolles theorem can be applied to #f (x)= 10 sin (2x)# on the interval [0,2pi] and if so how do you find all the values of c in the interval for which f' (c)=0?
Find x where pi <= x <= 2pi? 4 cos^2 x - 2= sec^2 x - tan^2 x
(4pi)/3; (11pi)/6 4cos^2 x - 2 = sec^2 x - tan^2 x (1) Develop the right side: RS = 1/ (cos^2 x) - sin^2 x/ (cos^2 x) = (1 - sin^2 x)/ (cos^2 x) = cos^2 x/ (cos^2 x) = 1 The equation (1) becomes: …
Question #92618 - Socratic
Explanation: We know path difference # delta x# and phase difference # delta phi# are related as, # delta phi = (2pi)/lambda delta x# we know, wave velocity (#v#) = wavelength (#lambda#) * …
Question #af5d8 - Socratic
a. cos 2x = 0 Unit circle gives: 2x = pi/2 + 2kpi and 2x = (3pi)/2 + 2kpi 2x = pi/2 + 2kpi --> x = pi/4 + kpi 2x = (3pi)/2 + 2kpi --> x = (3pi)/4 + kpi Answers for (0, 2pi): pi/4; (3pi)/4; (5pi)/4; (7pi)/4 b. …
Question #20f5c - Socratic
1.416xx10^7J, rounded to three decimal places. In any circular orbit, the centripetal force required to maintain the orbit is provided by the gravitational force on the satellite. Let r be the orbital …
What are the important points to graph y=3cos x? | Socratic
Dec 7, 2015 · I would say the important points are the zeroes, peaks, and troughs from 0 to 2pi radians.
Question #b59d5 - Socratic
These are the integrals needed for the areas of the piecewise functions: Some will be negative, because they are below the axis. int_0^ (pi/2) (x) dx=1/8pi^2 int_ (pi/2)^pi (x)dx=1/8pi^2 int_pi^ …
Question #2c5a4 - Socratic
where # (2pi^2me^4K^2)/ (ch^3)=109678cm^-1=R# (Rydberg's constant)or 1.09x #10^-7m^-1#
How do you find the volume of the solid generated by revolving …
V = 2piint_a^b xf (x)dx where: x is the radius of the shell f (x) is the thickness of the shell 2pi indicates that the shell is fully revolved (2pi radians = 1 full revolution) Now it's just a matter of …